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Fundamentals of Chemical Engineering Thermodynamics (1st) Edition 0132693062 9780132693066
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Problem 1P
Chapter
CH1
  • CH1
  • CH2
  • CH3
  • CH4
  • CH5
  • CH6
  • CH7
  • CH8
  • CH9
  • CH10
  • CH11
  • CH12
  • CH13
  • CH14
Problem
1P
  • 1P
  • 2P
  • 3P
  • 4P
  • 5P
  • 6P
Step-by-step solution
Step 1 of 6

a)

Specific volume is defined as the quantity of volume occupied by unit mass of substance and is denoted by . Mathematically, specific volume is equal to inverse of density of that substance and density is denoted by .

Density of ammonia, is equal to .

Substitute for in equation (1) to calculate the specific volume of ammonia, .

Step 2 of 6

The relation between and is as follows:

The relation between and is as follows:

Step 3 of 6

Multiply the specific volume with suitable conversion factor to calculate in terms of .

Multiply the specific volume with suitable conversion factors to calculate in terms of .

Therefore, specific volume is , and .

Step 4 of 6

b)

Write the relation between the specific volume and molar volume as follows:

Specific volume of ammonia, is equal to .

Calculate the molar mass of ammonia as follows:

Multiply specific volume with molar mass of ammonia to calculate the molar volume of ammonia.

Step 5 of 6

The relation between the and is,

The relation between the and is,

The relation between the and is,

Step 6 of 6

Multiply molar volume with suitable conversion factor to calculate the molar volume in terms of .

Multiply molar volume with suitable conversion factors to calculate the molar volume in terms of .

Therefore, the molar volume in different units are , and.

Corresponding textbook


Fundamentals of Chemical Engineering Thermodynamics | 1st Edition
Fundamentals of Chemical Engineering Thermodynamics | 1st Edition
ISBN-13:9780132693066ISBN:0132693062Authors:Themis Matsoukas Rent | Buy
Alternate ISBN: 9780132693165, 9780133134353
Alternate ISBN: 9780132693165, 9780133134353
Fundamentals of Chemical Engineering Thermodynamics (1st Edition) Edit edition…
Chapter 1, Problem 1P is solved.
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