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Fennema’s Food Chemistry, Fifth Edition (5th Edition) Edit editionThis problem has been solved:
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Problem 1CP
Chapter
CH3
- CH3
- CH15
Problem
1CP
- 1CP
- 2CP
- 3CP
- 4CP
- 5CP
- 6CP
- 7CP
- 8CP
- 9CP
- 10CP
- 11CP
- 12CP
- 13CP
- 14CP
- 15CP
- 16CP
- 17CP
- 18CP
- 19CP
- 20CP
Step-by-step solution
Step 1 of 4
Mannose is a carbohydrate, hexose, monosaccharide, which forms in the body which is very important for the metabolism, mainly in glycosylation of proteins involved in the transport. It is an epimer of glucose at C2 position.
Step 2 of 4
It is an aldohexose structure, which have 4 chiral carbons. In the mannose structure which made up of 6 carbon compounds which configures aldehyde group at first carbon. In the orientation of OH group at 5th carbon it is classified into D mannose and L mannose structures.
Step 3 of 4
The orientation of the carbon is based on the optical rotation when a plane polarized light passes into the sugar solution. It is role as metabolite, D form is active form of mannose, L forms seen in archea group of bacteria.
Step 4 of 4
Fischer structure of mannose developed structure is illustrated below as
Corresponding textbook
Fennema’s Food Chemistry, Fifth Edition | 5th Edition
Alternate ISBN: 9781482208139
Alternate ISBN: 9781482208139
Fennema’s Food Chemistry, Fifth Edition (5th Edition) Edit edition
Chapter 3, Problem 1CP is solved.
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