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12-Lead ECG (2nd) Edition 763773514 9780763773519
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12-Lead ECG (2nd Edition) Edit edition
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Solutions for Chapter 4…

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Problem 1CR
Chapter
CH4
  • CH1
  • CH2
  • CH3
  • CH4
  • CH6
  • CH7
  • CH8
  • CH9
  • CH10
  • CH11
  • CH12
  • CH13
  • CH14
  • CH15
  • CH16
Problem
1CR
  • 1CR
  • 2CR
  • 3CR
  • 4CR
  • 5CR
  • 6CR
  • 7CR
  • 8CR
  • 9CR
  • 10CR
Step-by-step solution
Step 1 of 6

Electrical activity in the heart is detected by the leads (electrodes) and is converted into waves by the electrocardiogram (ECG) machine. The ECG machine traces the wave and segment pattern on the ECG paper by the pen.

Step 2 of 6

The ECG paper is comprised of big boxes and each big box is made up of 5 little boxes (1mm each). The speed at which the paper passes under the pen is standardized. The speed of the ECG paper is maintained at 25 mm/sec. Therefore, each little box represents 1/25th i.e., 0.04 seconds and big box represents i.e., 0.20 seconds.

Step 3 of 6

The answers given in options (A), (B) and (C) are greater than 25 mm/sec. Also, the answer given in option (D) is correct and therefore option (E), stating ‘none of the above’ is not correct.

Step 4 of 6

Hence, options (A), (B), (C) and (E) are not the correct answers.

Step 5 of 6

The rate of passing of the ECG paper under the pen is 25 mm/sec.

Step 6 of 6

Hence, the correct answer is option.

Corresponding textbook


12-Lead ECG | 2nd Edition
12-Lead ECG | 2nd Edition
ISBN-13:9780763773519ISBN:763773514Authors:Tomas B Garcia Rent | Buy
Alternate ISBN: 9781284053456
Alternate ISBN: 9781284053456
12-Lead ECG (2nd Edition) Edit editionSolutions for Chapter 4…

Solutions for problems in chapter 4

Chapter 4, Problem 1CR is solved.