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12-Lead ECG (2nd Edition) Edit editionThis problem has been solved:Solutions for Chapter 14
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Problem 1CR
Chapter
CH14
- CH1
- CH2
- CH3
- CH4
- CH6
- CH7
- CH8
- CH9
- CH10
- CH11
- CH12
- CH13
- CH14
- CH15
- CH16
Problem
1CR
- 1CR
- 1M9
- 1QR1
- 1QR2
- 1QR3
- 1QR4
- 1QR5
- 1QR6
- 1QR7
- 1QR8
- 1QR9
- 2CR
- 2QR1
- 2QR2
- 2QR3
- 2QR4
- 2QR5
- 2QR6
- 2QR7
- 2QR8
- 2QR9
- 3CR
- 3QR1
- 3QR2
- 3QR3
- 3QR4
- 3QR5
- 3QR6
- 3QR7
- 3QR8
- 4CR
- 4QR5
- 5CR
- 5QR5
- 6CR
- 7CR
- 8CR
- 9CR
- 10CR
- 11CR
- 12CR
- 13CR
- 14CR
- 15CR
Step-by-step solution
Step 1 of 4
519540-14-1CR AID: 51968 | 05/06/2020
Step 2 of 4
Electrical activity in the heart is detected by the leads (electrodes) and is converted into waves by the electrocardiogram (ECG) machine. The ECG machine traces the wave and segment pattern on the ECG paper by the pen.
Step 3 of 4
ST-segment is the section of complex where the ventricles are between the electrical depolarization and repolarization. The measurement of the segment is taken from the J point, the meeting point of the QRS complex and ST segment to the beginning of T wave.
Step 4 of 4
Hence, the given statement is 
Corresponding textbook
12-Lead ECG | 2nd Edition
Alternate ISBN: 9781284053456
Alternate ISBN: 9781284053456
Chapter 14, Problem 1CR is solved.
